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-.06x^2-4x+.5x+6x=
We move all terms to the left:
-.06x^2-4x+.5x+6x-()=0
We add all the numbers together, and all the variables
-0.06x^2+2.5x=0
a = -0.06; b = 2.5; c = 0;
Δ = b2-4ac
Δ = 2.52-4·(-0.06)·0
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{6.25}}{2*-0.06}=\frac{-2.5-\sqrt{6.25}}{-0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{6.25}}{2*-0.06}=\frac{-2.5+\sqrt{6.25}}{-0.12} $
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